How do I solve this "Aqueous iron(II) chloride reacts with aqueous lithium bromide to form aqueous iron(II) bromide and aqueous lithium bromide."
Don't quote me on this cause I looked it up but maybe: Aqueous iron(II) chloride + aqueous ammonium hydroxide Balanced Molecular Equation
www.homeworklib.com/question/1016136/reaction-14-aqueous-ironii-chloride-aqueous Heres the link I used
There is a formula that I have to put down as the answer and I am confused.
Iron ¡¡ chloride reacts with lithium to form lithium chloride and iron
I am bad at science but maybe try a different site like brainly is a good one because it has answers that are fact-checked plus the answers come with explanations.
"Aqueous iron(II) chloride reacts with aqueous lithium bromide to form aqueous iron(II) bromide and aqueous lithium bromide."
FeCl2(aq) + 2LiBr(aq) ==> FeBr2(aq) + 2LiCl(aq)
This the balanced chemical equation translated from the word equation. I have a word of caution, however, that reaction looks good on paper but it will not occur as written nor will it occur in the reverse direction. It simply is an balanced equation. It gives practice in formula writing and in balancing but it is simply and exercise and not a real workable equation. Thanks for using Jiskha. As for Brainly, I have looked at that site numerous times and I've always found the answers very good and correct. However, personally, I think they are slow and you don't have other similar questions to peruse. So I continue to help on Jiskha.
To solve this chemical equation, you'll need to balance it by ensuring that the same number of each type of atom is present on both sides of the equation.
First, write out the unbalanced equation:
FeCl2(aq) + LiBr(aq) -> FeBr2(aq) + LiCl(aq)
Now, let's balance each element one by one:
1. Start with the least common atom: lithium (Li).
Here, we have one lithium atom on the left side and one on the right side, so lithium is already balanced.
2. Next, balance the chlorine (Cl) and bromine (Br) atoms.
On the left side, we have two chlorine atoms (2 Cl) in FeCl2, but only one bromine atom (1 Br) in LiBr.
On the right side, we have two bromine atoms (2 Br) in FeBr2, but only one chlorine atom (1 Cl) in LiCl.
To balance Cl and Br, we need to adjust the coefficients in front of each compound to achieve an equal number of atoms on both sides:
FeCl2(aq) + 2 LiBr(aq) -> FeBr2(aq) + 2 LiCl(aq)
Now, all the elements are balanced, and the equation is properly balanced.
To summarize the steps:
1. Identify each element and count the number of atoms of each element on both sides of the equation.
2. Balance the least common atom first, then proceed to the other atoms.
3. Adjust the coefficients in front of each compound to balance the atoms on both sides.
4. Finally, double-check to ensure all elements are balanced.