General Chemistry

A solution was prepared by dissolving 18.00 grams glucose in 150.0 grams water. The resulting solution was found to have a boiling point of 100.34 0C. Calculate the molar mass of glucose. (Kb (water) = 0.51 0C kg/mol; Tb(water) = 80. 0 0C)

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  1. I'm not sure what you mean for Tb = 80. If you mean boiling point for H2O that is 100 C and that's the number I will use.
    delta T = Kb*molality
    100.34-100 = 0.34 =*0.51 molality.
    Solve for molality = mols/Kg solvent.
    You know m and you know kg solvent is 0.150. Solve for mols.
    Then mols = grams/molar mass. You know mols and grams, solve for molar mass = ?
    Post your work if you get stuck. I ran through the calculations in my head and got about 180 g/mol.

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    DrBob222
  2. Nothing

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  3. yes

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