AARON’S FATHER IS NINE TIMES AS OLD AS HE IS. ONE YEAR AGO, HE WAS TWO YEARS MORE THAN 11
TIMES AS OLD AS AARON. FIND AARON’S PRESENT AGE.
Sink
Let's solve this step-by-step.
Let's assume Aaron's present age is "x".
According to the problem, Aaron's father is nine times as old as Aaron, so his age would be 9x.
One year ago, Aaron was x - 1 years old, and his father was 9x - 1 years old.
At that time, Aaron's age was two years more than 11 times as old as Aaron, so we can set up the equation:
x - 1 = 11(x - 1) + 2
Now let's solve for x:
x - 1 = 11x - 11 + 2
x - 1 = 11x - 9
Subtract x from both sides:
-1 = 10x - 9
Add 9 to both sides:
8 = 10x
Divide both sides by 10:
x = 0.8
So, Aaron's present age would be approximately 0.8 years.
To find Aaron's present age, we can follow the given information and solve the problem step by step.
Let's assume Aaron's present age is x years.
According to the first statement, Aaron's father is nine times as old as Aaron. Therefore, Aaron's father's age is 9x years.
Now, let's consider the second statement. It says that one year ago, Aaron was two years less than 11 times his present age. So, we need to calculate Aaron's age one year ago.
One year ago, Aaron's age would be x - 1.
According to the statement, 11 times Aaron's age minus two years would be his father's age one year ago:
11(x - 1) - 2 = 9x - 1
Simplifying the equation:
11x - 11 - 2 = 9x - 1
Combine like terms:
11x - 13 = 9x - 1
Subtract 9x from both sides:
11x - 9x - 13 = -1
Combine like terms:
2x - 13 = -1
Add 13 to both sides:
2x - 13 + 13 = -1 + 13
Combine like terms:
2x = 12
Divide both sides by 2:
2x/2 = 12/2
Simplifying:
x = 6
Therefore, Aaron's present age is 6 years.
let Aaron's present age be x
his father is 9x
One year ago, Aaron was x-1
dad was 9x-1
9x-1 = 11(x-1) + 2
etc
let us know what answer you got