2KCIO3 → 2KCI + 3O2
For the reaction above, use the balanced equation to determine how many moles of Oxygen would be needed to produce 8 moles of potassium chlorate.
The answer is zero. No amount of oxygen will produce KClO3. What you meant to ask, I'm sure, is "how many moles of KClO3 will be needed to produce 8 moles O2. That answer is
8 moles O2 x (2 moles KClO3/3 mols O2) = 8*2/3 = 16/3 mols
2KCIO3 → 2KCI + 3O2
To determine how many moles of oxygen are needed to produce 8 moles of potassium chlorate, we first need to find the molar ratio between oxygen and potassium chlorate.
By looking at the balanced equation:
2KClO3 → 2KCl + 3O2
We can see that for every 2 moles of potassium chlorate, 3 moles of oxygen are produced.
Since the equation is balanced in a 1:1 ratio for the reactants and products, we can conclude that the molar ratio between potassium chlorate and oxygen is 2:3. This means that for every 2 moles of potassium chlorate, 3 moles of oxygen are needed.
In this case, we are producing 8 moles of potassium chlorate. To determine how many moles of oxygen are required, we can set up a simple proportion:
(3 moles O2 / 2 moles KClO3) = (x moles O2 / 8 moles KClO3)
Cross-multiplying and solving for x, we get:
3 moles O2 * 8 moles KClO3 = 2 moles KClO3 * x moles O2
24 moles O2 = 2x moles O2
Dividing both sides by 2, we find:
12 moles O2 = x moles O2
Therefore, 8 moles of potassium chlorate would require 12 moles of oxygen to produce.