Given the functions k(x) = 5x − 8 and p(x) = x − 4, solve k[p(x)].
k[p(x)] = 5x − 12
k[p(x)] = 5x − 28
k[p(x)] = 5x2 − 12
k[p(x)] = 5x2 − 28
To solve k[p(x)], we need to substitute p(x) into the function k(x).
First, let's find p(x). The function p(x) is defined as p(x) = x - 4.
Next, we substitute p(x) into k(x), which gives us k[p(x)] = k(x - 4).
Now, we substitute the expression x - 4 into k(x) to get k[p(x)] = 5(x - 4) - 8.
Simplifying this expression, we have k[p(x)] = 5x - 20 - 8.
Combining like terms, we get k[p(x)] = 5x - 28.
Therefore, the solution is k[p(x)] = 5x - 28.
k(x) = 5x − 8 and p(x) = x − 4, solve k[p(x)]
"solve" is not the correct instruction here, should say "find"
k[p(x)] = k[x-4]
= 5(x-4) - 8
= .....