if someone rolls a cube 60 times how many times would it take them to roll a number less than 3?
A]10 B]20 C]30 D]40 E]50
well, 2 of the 6 numbers are less than 3, so you'd expect 2/6 of the rolls to be okay.
To solve this problem, we need to calculate the probability of rolling a number less than 3 on a single roll of the cube.
A standard cube has six faces, numbered from 1 to 6. We want to find the probability of rolling a number less than 3, which includes the numbers 1 and 2. So, out of the six faces, two of them satisfy this condition.
The probability of rolling a number less than 3 can be calculated as follows:
Probability = Number of favorable outcomes / Total number of outcomes
= 2 / 6
= 1 / 3
Now, let's imagine rolling a cube 60 times. The probability of rolling a number less than 3 on each individual roll will remain constant at 1/3.
To determine how many times it would take to roll a number less than 3, we can use the concept of expected value. The expected value of an event is the average value we would expect to occur over a large number of occurrences. In this case, the expected value will help us determine the average number of successes (rolls less than 3) in a sequence of independent events (rolling the cube repeatedly).
The expected number of successes can be calculated as:
Expected number of successes = Probability of success x Total number of trials
= (1/3) x 60
= 20
Therefore, it would be expected that you would roll a number less than 3 approximately 20 times if you rolled the cube 60 times. However, keep in mind that this is an average value and the actual number of times may vary.