1) Write a balanced equation for the reaction between diprotic carbonic acid and monohydroxy compound named potassium hydroxide, each as aqueous solutions. Also give the two classes of this reaction.
So, H2CO3 for carbonic acid and KOH for potassium hydroxide. Is this some special type of reaction?
I got, H2CO3+2KOH ---> K2CO3 + 2H2O.
A double displacement. Is this right?
The equation is right. Balancing is right. This is an acid/base neutralization reaction.
Yes, you are correct. The balanced equation for the reaction between diprotic carbonic acid (H2CO3) and monohydroxy compound potassium hydroxide (KOH) is:
H2CO3 + 2KOH → K2CO3 + 2H2O
This reaction is a type of double displacement reaction, also known as a neutralization reaction. In this reaction, the hydrogen ions (H+) from the carbonic acid react with the hydroxide ions (OH-) from the potassium hydroxide, resulting in the formation of water (H2O). Additionally, the potassium ions (K+) from the base react with the carbonate ions (CO3^2-) from the acid, forming potassium carbonate (K2CO3).
Yes, you are correct. The balanced equation for the reaction between diprotic carbonic acid (H2CO3) and monohydroxy compound potassium hydroxide (KOH) is:
H2CO3 + 2KOH → K2CO3 + 2H2O
This is a double displacement reaction, also known as a metathesis reaction or a precipitation reaction. In this type of reaction, the positive and negative ions of two different compounds switch places to form two new compounds. In the given reaction, the hydrogen ions (H+) from carbonic acid combine with the hydroxide ions (OH-) from potassium hydroxide, forming water (H2O). Simultaneously, the potassium ions (K+) from potassium hydroxide combine with the carbonate ions (CO3^2-) from carbonic acid, forming potassium carbonate (K2CO3).