there are 3 parts to my question. i need help on the last part.
1.a. A child rides a bike in a circular path with a radius of 2.0 m. The tangential speed of the bike is 2.0 m/s. The combined mass of the bike and the child is 43 kg. What is the magnitude of the bike's centripetal acceleration?
i got 2.0 m/s^2
b., What is the magnitude of the centripetal force on the bike?
i got 86 N
c. What kind of force provides the centripetal force on the bike?
i don't know,... gravitational force, friction, air resistance, or normal force
thanks for the help!
c. A centripetal friction force on the wheels, applied at the ground and perpendicular to the direction of motion, provides the force that keeps the bike going in a circle
Spokes provide the centripetal force toward the axle of the wheel, but they did not ask for that.
so friction
Friction in a particular sideways direction. There is also forward/backward friction when accelerating, decelerating or climbing hills
To find the magnitude of the bike's centripetal acceleration, you can use the formula:
Centripetal acceleration (a) = (tangential speed)^2 / radius
In this case, the tangential speed is given as 2.0 m/s, and the radius is given as 2.0 m. Plugging these values into the formula, we get:
a = (2.0 m/s)^2 / 2.0 m = 4.0 m^2/s^2
So, the magnitude of the bike's centripetal acceleration is indeed 4.0 m/s^2, which matches your answer.
To find the magnitude of the centripetal force on the bike, you can use the equation:
Centripetal force (F) = mass × centripetal acceleration
The combined mass of the bike and the child is given as 43 kg, and the centripetal acceleration is 4.0 m/s^2. Plugging these values into the equation, we get:
F = 43 kg × 4.0 m/s^2 = 172 N
So, the magnitude of the centripetal force on the bike is 172 N, which doesn't match your answer of 86 N. Please double-check your calculations for this part.
Now, for the last part of the question, what kind of force provides the centripetal force on the bike? Centripetal force is defined as the force that keeps an object moving in a circular path. In this case, since the bike is not in contact with any other object (such as the ground or a string), the centripetal force must be provided by the force of friction between the bike's tires and the ground. Therefore, the correct answer is friction.