chemistry

A solution is prepared by dissolving 10.00 g of glucose, C6H12O6, in 500 g of water. The
final volume of the solution is 415 mL
i)Determine the moles of glucose, C6H12O6
ii)Calculate the molality of the solution

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  1. molar mass C6H12O6 = 180
    mols glucose = grams/molar mass = 10.00/180 = ?
    molality = mols glucose/kg solvent = mols glucose/0.500 = ?

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    DrBob222

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