Parks is wearing several rubber bracelets. 1/3 of the bracelets are tie-dye, 1/6 are blue, and 1/3 of the remainder are camouflage. If Parks wears 2 camouflage bracelets, how many bracelets does he have on?
1 - 1/3 - 1/6 = 1/2
1/3 * 1/2 = 1/6
1/6 x = 2
Parks is wearing several rubber bracelets. 1 third of the bracelets are tie-dye, 1 over 6 are blue, and 1 third of the remainder are camouflage. If Parks wears 2 camouflage bracelets, how many bracelets does
To find out how many bracelets Parks has on, we need to go step by step through the information given.
The problem states that 1/3 of the bracelets are tie-dye, and 1/6 are blue. This means that the remaining bracelets, which are neither tie-dye nor blue, make up 1 - (1/3 + 1/6) of the total number of bracelets.
To simplify, let's find a common denominator for 1/3 and 1/6, which is 6.
1/3 + 1/6 = 2/6 + 1/6 = 3/6 = 1/2.
So, the remaining bracelets, which are neither tie-dye nor blue, make up 1/2 of the total number of bracelets.
The problem then states that 1/3 of the remainder are camouflage bracelets. So, we can find the number of camouflage bracelets by multiplying the remaining bracelets (1/2) by 1/3:
(1/2) * (1/3) = 1/6.
Therefore, 1/6 of the total number of bracelets are camouflage bracelets.
It is given that Parks wears 2 camouflage bracelets. So, we can set up the equation:
1/6 * Total number of bracelets = 2.
To solve for the total number of bracelets, we can multiply both sides of the equation by the reciprocal of 1/6, which is 6/1:
(1/6) * (6/1) * Total number of bracelets = 2 * (6/1).
Simplifying, we get:
Total number of bracelets = 12.
Therefore, Parks has a total of 12 bracelets on.