a wheelbarrow inclined at 30° to the horizontal is push with a force of 150. i) what is the vertically component of the applied force.ii) what is the horizontal component of the applied force. iii) in what direction will the wheelbarrow move and why
Am I missing something? The wheelbarrow has to move in the direction of the net force. Newtons law of motion.
i) To find the vertical component of the applied force, we need to determine the amount of force acting in the vertical direction. This can be found by taking the cosine of the angle of inclination and multiplying it by the magnitude of the applied force.
Vertical component of the applied force = Applied force * cos(angle of inclination)
Given:
Applied force = 150
Angle of inclination = 30°
Vertical component of the applied force = 150 * cos(30°)
Using a calculator, we find:
Vertical component of the applied force = 150 * 0.866
Vertical component of the applied force ≈ 129.9
ii) Similarly, to find the horizontal component of the applied force, we need to determine the amount of force acting in the horizontal direction. This can be found by taking the sine of the angle of inclination and multiplying it by the magnitude of the applied force.
Horizontal component of the applied force = Applied force * sin(angle of inclination)
Horizontal component of the applied force = 150 * sin(30°)
Using a calculator, we find:
Horizontal component of the applied force = 150 * 0.5
Horizontal component of the applied force = 75
iii) The wheelbarrow will move in the direction of the horizontal component of the applied force. This is because the horizontal component is responsible for pushing the wheelbarrow forward. Therefore, the wheelbarrow will move in the same direction as the applied force, which in this case is horizontally.
To solve this problem, we need to analyze the forces acting on the wheelbarrow.
i) The vertically component of the applied force can be found using the formula:
Vertical Component = Force * sin(θ)
where θ is the angle of inclination (30°) and the force is 150 N.
Vertical Component = 150 N * sin(30°)
Vertical Component = 150 N * 0.5
Vertical Component = 75 N
The vertically component of the applied force is 75 N.
ii) The horizontal component of the applied force can be calculated using the formula:
Horizontal Component = Force * cos(θ)
where θ is the angle of inclination (30°) and the force is 150 N.
Horizontal Component = 150 N * cos(30°)
Horizontal Component = 150 N * 0.866
Horizontal Component ≈ 129.9 N
The horizontal component of the applied force is approximately 129.9 N.
iii) The wheelbarrow will move in the direction of the horizontal force component. Since the wheelbarrow is inclined at an angle of 30° to the horizontal, the horizontal component of the applied force (129.9 N) is acting parallel to the ground.
Therefore, the wheelbarrow will move in the direction of the applied force, which is in the horizontal direction.
In summary:
i) The vertically component of the applied force is 75 N.
ii) The horizontal component of the applied force is approximately 129.9 N.
iii) The wheelbarrow will move in the horizontal direction, as the applied force is acting parallel to the ground.