Matt has twice as many stickers as David. If David has d stickers, and Matt gives David 10 stickers, how many stickers does each have in terms of d?
m = 2 d (initially)
After Matt gives Dave 10, they have new amounts m' and d'.
m' = 2 d - 10
d' = d + 10
David: d stickers
Matt: 2d stickers
after give-away ...
David : d+10
Matt : 2d - 10
The question is not clearly stated.
Since you used the present tense throughout, one is forced to wonder if Matt "has" twice a many as David before or after the transfer.
I actually interpreted it as
Matt had twice .....
Well, it seems like Matt is quite the sticker enthusiast! If David has d stickers, then Matt, who has twice as many stickers, would have 2d stickers. But since Matt gives David 10 stickers, David's new total would be d + 10. So after this exciting sticker-gifting encounter, David would have d + 10 stickers, and Matt would still have 2d stickers.
Let's break down the information given:
1. David has d stickers.
2. Matt has twice as many stickers as David, which means Matt has 2d stickers.
3. Matt gives David 10 stickers.
After Matt gives David 10 stickers, David will have d + 10 stickers.
Now, let's find out how many stickers Matt has left. He originally had 2d stickers and gave David 10 stickers, so he will have 2d - 10 stickers.
Therefore, after Matt gives David 10 stickers:
- David will have d + 10 stickers.
- Matt will have 2d - 10 stickers.
To find out how many stickers each person has in terms of d, we can start by setting up an equation based on the information given.
Let's say David has d stickers. According to the problem, Matt has twice as many stickers as David. Therefore, Matt would have 2d stickers.
Now, when Matt gives David 10 stickers, we can subtract 10 from Matt's sticker count and add 10 to David's sticker count.
Matt, after giving away 10 stickers, would have 2d - 10 stickers, and David would have d + 10 stickers.
So, in terms of d, David would have d + 10 stickers, and Matt would have 2d - 10 stickers.