Question

A bag of marbles has 3 red, 2 blue and 4 green. What is the likelihood of pulling a red, not replacing it, then pulling a red?

Answer 1

3/9 * 2/8 = ___

Answer 2

Wow thanks

Answer 3

[AI-generated answer — Explain Bot]

To calculate the likelihood of pulling a red marble, not replacing it, and then pulling another red marble, we need to follow these steps:

Step 1: Calculate the probability of pulling the first red marble.
First, determine the total number of marbles in the bag: 3 red + 2 blue + 4 green = 9 marbles.
The probability of pulling a red marble on the first draw is therefore 3 red marbles / 9 total marbles = 1/3.

Step 2: Calculate the probability of pulling a second red marble without replacement.
After the first red marble is pulled, there are now 2 red marbles and 8 marbles remaining in the bag. Thus, the probability of pulling a second red marble without replacement is 2 red marbles / 8 remaining marbles = 1/4.

Step 3: Multiply the probabilities together.
To find the likelihood of both events happening, we multiply the probabilities of each step together:
(1/3) * (1/4) = 1/12.

Therefore, the likelihood of pulling a red marble, not replacing it, and then pulling another red marble is 1/12.