Gabriel has these cans of soup in his kitchen cabinet.
• 2 cans of tomato Soup
• 3 cans of chicken soup
• 2 cans of cheese soup
• 2 cans of potato soup
• 1 can of beef soup
Gabriel will randomly choose one can of soup. Then he will put it back and randomly choose another can of soup. What is the probability that he will choose a can of tomato soup and then a can of cheese soup.
Thank you .....
Saved me some trouble :)
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To determine the probability of Gabriel choosing a can of tomato soup and then a can of cheese soup, we need to divide the number of favorable outcomes (choosing a can of tomato soup and then a can of cheese soup) by the total number of possible outcomes (choosing any two cans of soup from the given options).
Let's break it down step by step:
Step 1: Determine the number of favorable outcomes (choosing a can of tomato soup and then a can of cheese soup):
Since Gabriel has 2 cans of tomato soup and 2 cans of cheese soup, he has 2 choices for the first soup (tomato soup) and 2 choices for the second soup (cheese soup). Therefore, the number of favorable outcomes is 2 x 2 = 4.
Step 2: Determine the total number of possible outcomes (choosing any two cans of soup):
Since Gabriel has a total of 10 cans of soup, he has 10 choices for the first soup and 10 choices for the second soup. Therefore, the total number of possible outcomes is 10 x 10 = 100.
Step 3: Calculate the probability:
Now that we have the number of favorable outcomes (4) and the total number of possible outcomes (100), we can calculate the probability:
Probability = Number of favorable outcomes / Total number of possible outcomes
Probability = 4 / 100
Probability = 0.04
Therefore, the probability that Gabriel will choose a can of tomato soup and then a can of cheese soup is 0.04 or 4%.