An aircraft landing on an aircraft carrier is brought to a complete

stop from an initial velocity of 215 km/h in 27 seconds. What is its
acceleration in m/s²

(-215 km/hr * 1hr/3600s * 1000m/km) / 27s = -(215*1000)/(3600*27) = -2.2 m/s^2

Thanks

To find the acceleration of an aircraft, you can use the basic equation of motion:

acceleration (a) = (final velocity - initial velocity) / time

Given:
Initial velocity (u) = 215 km/h
Time (t) = 27 seconds

Before we calculate the acceleration, let's convert the initial velocity from km/h to m/s:
1 km/h = 1000 m / 3600 s = 5/18 m/s

Initial velocity (u) = 215 km/h * (5/18 m/s per 1 km/h) = 59.72 m/s

Now we can calculate the acceleration using the equation:

acceleration (a) = (final velocity - initial velocity) / time
= (0 m/s - 59.72 m/s) / 27 s
= -59.72 m/s / 27 s
= -2.212 m/s² (rounded to three decimal places)

Therefore, the acceleration of the aircraft landing on the aircraft carrier is approximately -2.212 m/s². The negative sign indicates that the aircraft is decelerating or slowing down.