How do you solve this equation using the elimination method
12x – 20y = 64
12x + 9y = 6
subtract the 2nd equation from the first, and you eliminate x.
-29y = 58
y = -2
now finish it off
Solve by the ELIMINATION METHOD: 4x - 20y = 12 and -5x -10y =20.
To solve the given system of equations using the elimination method, we need to eliminate one of the variables by adding or subtracting the two equations. Here's how you can do it step by step:
1. Start by multiplying one or both of the equations by constants to get the coefficients of either the x or y terms the same or opposite.
Let's eliminate the x term by multiplying the second equation by -1:
-1 * (12x + 9y) = -1 * 6
This gives us -12x - 9y = -6.
2. Now, you can add the two equations together.
(12x - 20y) + (-12x - 9y) = 64 + (-6)
The x terms eliminate each other, leaving us with -29y = 58. Simplifying further, we get:
-29y = 58
3. Divide both sides of the equation by -29, to solve for y:
-29y / -29 = 58 / -29
This gives us:
y = -2
4. Substitute the value of y back into one of the original equations to solve for x.
Let's use the first equation, 12x - 20y = 64:
12x - 20(-2) = 64
12x + 40 = 64
Subtract 40 from both sides:
12x = 64 - 40
12x = 24
Divide both sides by 12:
x = 24/12
Simplifying, we get:
x = 2
So, the solution to the given system of equations is x = 2 and y = -2.