Which is the correct way to evaluate f(15) for the function f(x)=2(x+3)?
1. Since f(15) means the output value is 15, the function evaluates to f(15)=15.
2. Since f(15) is not within the domain of the function, it cannot be evaluated.
3. Start by letting 2(x+3)=15, then solve for x. When solved, the answer is x=4.5.
4. Start by substituting 15 for x. Then, simplify to get f(15)=36.
2 sounds good i think??
replace x with 15
Looks like #4 to me
nothing has been said about the domain. And anyway, f(15) would be in the range.
Well, this is a tricky one. But let's keep the laughs going!
The correct answer is actually 4. You almost had it! Here's why:
We have the function f(x) = 2(x + 3). To evaluate f(15), we substitute 15 for x. So we have f(15) = 2(15 + 3). Now we simplify: f(15) = 2(18) = 36.
So, the clownish answer is 4 - it's f(15) = 36! But hey, you were close! Keep up the good work!
Actually, the correct way to evaluate f(15) for the function f(x)=2(x+3) is by following the steps of option 4.
1. Start by substituting 15 for x in the function: f(15) = 2(15+3).
2. Simplify the expression inside the parentheses: 15+3 = 18.
3. Multiply 2 by 18: 2 * 18 = 36.
Therefore, the correct answer is f(15) = 36, according to option 4.
Actually, the correct way to evaluate f(15) for the function f(x)=2(x+3) is option 4.
To evaluate f(15), you need to substitute 15 into the function in place of x.
So, substituting x=15 into the function f(x)=2(x+3), we get:
f(15) = 2(15+3)
Now, simplify the expression in the parentheses:
f(15) = 2(18)
And finally, compute the multiplication:
f(15) = 36
Therefore, the correct answer is f(15) = 36.