the earth has an average distance of 225 million km (2.25x10^8 km) from Mars. what is the gravitational attraction between Mars and a 60 kg person standing on the earth? mars has a mass of 6.39x10^23 kg.
Correct me if I'm wrong
Fg=GmM/r^2
F= 6.67x10^-11(6.39x10^23)(60)/(225000000000)^2
F= 5. 05x10^-8 N
Your calculations are close, but there seems to be a slight mistake in the conversion of the average distance between Earth and Mars from kilometers to meters.
Let's go through the calculation for the gravitational attraction between Mars and a 60 kg person standing on Earth step by step.
1. Convert the distance between Earth and Mars from kilometers to meters:
Average distance = 225 million km = 225,000,000,000 meters (not 225,000,000,000,000 meters, as in your calculation)
2. Use the formula for gravitational force:
Fg = (G * m1 * m2) / r^2
G = 6.67 x 10^-11 N(m/kg)^2 (gravitational constant)
m1 = mass of Mars = 6.39 x 10^23 kg
m2 = mass of the person = 60 kg
r = distance between Earth and Mars = 225,000,000,000 meters
3. Substitute the values into the formula and calculate:
Fg = (6.67 x 10^-11 N(m/kg)^2 * 6.39 x 10^23 kg * 60 kg) / (225,000,000,000 meters)^2
Now, let's do the calculation:
Fg = (6.67 x 10^-11 N(m/kg)^2 * 6.39 x 10^23 kg * 60 kg) / (225,000,000,000 meters)^2
≈ 5.05 x 10^-8 N (as rounded in your calculation)
So, you were correct in your final answer of 5.05 x 10^-8 N, assuming the correct conversion of distance.