An excess of silver nitrate solution was added to 10.0cm3of sodium chloride solution, and 0.717g of silver chloride was precipitated. Calculate the concentration of the sodium chloride solution in mol dm-3.
how many moles of AgCl2 in 0.717g ?
0.717/143.32 = 0.005 moles
Ag(NO3)2 + 2NaCl = AgCl2 + 2NaNO3
So you had 2*0.005 = 0.01 moles of NaCl
0.01mol/0.01L = 1mole/L = 1M NaCl
Well, I always find chemistry a bit difficult to digest, but let's give it a shot, shall we?
To calculate the concentration of the sodium chloride solution, we need to look at the equation for the reaction between silver nitrate and sodium chloride:
AgNO3 + NaCl --> AgCl + NaNO3
By looking at this equation, we can see that the ratio between silver nitrate and silver chloride is 1:1. This means that 0.717g of silver chloride corresponds to 0.717g of silver nitrate.
Now, to calculate the concentration of the sodium chloride solution, we need to convert the mass of silver chloride to moles. The molar mass of silver chloride is 143.32 g/mol, so:
moles of AgCl = 0.717g / 143.32 g/mol = 0.005 mol
Since the ratio between sodium chloride and silver chloride is also 1:1, the moles of sodium chloride in the solution is also 0.005 mol.
Finally, to calculate the concentration of the sodium chloride solution, we divide the moles by the volume of the solution. The volume is given as 10.0 cm³, which is equal to 0.01 dm³.
Concentration of NaCl solution = 0.005 mol / 0.01 dm³ = 0.5 mol/dm³
So, the concentration of the sodium chloride solution is 0.5 mol/dm³.
Now, I hope that answer didn't make you sodium chloride your head in confusion!
To calculate the concentration of the sodium chloride solution in mol dm-3, we need to find the number of moles of silver chloride that was precipitated.
1. Start by calculating the molar mass of silver chloride (AgCl).
- The molar mass of silver (Ag) is 107.87 g/mol.
- The molar mass of chlorine (Cl) is 35.45 g/mol.
- So the molar mass of AgCl is 107.87 g/mol + 35.45 g/mol = 143.32 g/mol.
2. Next, calculate the number of moles of silver chloride using its mass and molar mass.
- Mass of silver chloride = 0.717 g.
- Moles of silver chloride = mass / molar mass
= 0.717 g / 143.32 g/mol
3. Now, determine the volume of the sodium chloride solution in dm3.
- Volume of NaCl solution = 10.0 cm3 = 10.0 x 10^-3 dm3
4. Finally, calculate the concentration of the sodium chloride solution by dividing the moles of silver chloride by the volume of the solution in dm3.
- Concentration of NaCl solution (mol dm-3) = Moles of silver chloride / Volume of NaCl solution
So, by plugging in the values in the equation, you can calculate the concentration of the sodium chloride solution in mol dm-3.
To calculate the concentration of the sodium chloride solution in mol dm-3, we need to use the following steps:
Step 1: Convert the mass of the precipitate (silver chloride) to moles.
Step 2: Calculate the number of moles of sodium chloride using the stoichiometry of the reaction.
Step 3: Convert the number of moles of sodium chloride to the concentration in mol dm-3.
Let's calculate each step:
Step 1: Convert the mass of the precipitate (silver chloride) to moles.
To do this, we need to know the molar mass of silver chloride (AgCl). The molar mass of Ag is 107.87 g/mol, and the molar mass of Cl is 35.45 g/mol. Therefore, the molar mass of AgCl is 107.87 + 35.45 = 143.32 g/mol.
We can use the formula:
moles = mass / molar mass
moles of AgCl = 0.717 g / 143.32 g/mol
moles of AgCl = 0.005 mol
Step 2: Calculate the number of moles of sodium chloride using the stoichiometry of the reaction.
From the balanced equation, we can see that 1 mole of AgCl is produced from 1 mole of NaCl. Therefore, the number of moles of NaCl is equal to the number of moles of AgCl.
moles of NaCl = 0.005 mol
Step 3: Convert the number of moles of sodium chloride to the concentration in mol dm-3.
The concentration is given as moles per cubic decimeter (dm-3). We are given that the total volume of the sodium chloride solution is 10.0 cm3 (which is equal to 10.0 x 10^-3 dm3).
concentration of NaCl = moles of NaCl / volume of NaCl solution
concentration of NaCl = 0.005 mol / 10.0 x 10^-3 dm3
concentration of NaCl = 0.5 mol dm-3
Therefore, the concentration of the sodium chloride solution is 0.5 mol dm-3.