Grant pays $0.10 per minute plus $5.00 per month for international telephone calls. Write an algebraic expression for "m" minutes of international calls in one month.
A phone company has a monthly fee of L 600.00 and charges a rate of L 5.00 per minute of long distance calls. Another long distance company has a monthly fee of L 500 .00 and charges a rate of L 7.00 per minute. At how many minutes would the two companies have equal charges?
5.00 + 0.10m
To write an algebraic expression for "m" minutes of international calls in one month, you can use the given information that Grant pays $0.10 per minute plus $5.00 per month.
The cost per minute is $0.10, so the cost for "m" minutes of international calls would be 0.10m.
The monthly cost is $5.00, so the total cost for "m" minutes of international calls in one month would be 0.10m + 5.00.
Therefore, the algebraic expression for "m" minutes of international calls in one month is 0.10m + 5.00.
To write an algebraic expression for "m" minutes of international calls in one month, we need to consider the two components of the cost: the cost per minute and the fixed monthly cost.
The cost per minute is $0.10, so the total cost for "m" minutes would be 0.10m.
The fixed monthly cost is $5.00, which remains the same regardless of the number of minutes. So, the algebraic expression for the total cost of "m" minutes of international calls in one month would be:
Total cost = Cost per minute + Fixed monthly cost
Total cost = 0.10m + 5.00
Therefore, the algebraic expression for "m" minutes of international calls in one month is 0.10m + 5.00.