what is the value of x?
it is an isosceles triangle, standing upright _^ (move the line under triangle and thats the shape of it)
The top angle is 38 degrees, and the two side lines, the legs, are both 21 degrees.
x is the bottom right corner angle, how do i find x
The interior angles of any triangle add up to 180 degrees
2 x + 38 = 180
the legs, are both 21 degrees.
??? huh ????
21 meters maybe
if so then sin (38 / 2) = half the base / 21
so base length = 2* 21 * sin 19
To find the value of angle x in the given isosceles triangle, you can use the fact that the sum of the angles in any triangle is always 180 degrees.
In this case, you are given that the top angle is 38 degrees and the two side angles (legs) are both 21 degrees. Since the triangle is isosceles, this means that the top angle and the side angles are congruent (equal). Therefore, you can consider the triangle as having two 21-degree angles and one 38-degree angle.
To find the value of angle x, subtract the sum of the known angles (38 + 21 + 21 = 80 degrees) from 180 degrees:
x = 180 - 80 = 100 degrees.
Hence, the value of angle x is 100 degrees.