Create a rational expression with a variable m that has non-permissible values of 3 and –1.
again?
1 / (m-3)(m+1)
To create a rational expression with non-permissible values of 3 and -1, we need to use the concept of excluded values. To find the excluded values, we need to identify the values that make the denominator equal to zero. In this case, the denominator cannot be equal to zero, so we need to exclude the values that cause this.
Let's create the rational expression:
f(m) = 1 / (m - 3)(m + 1)
In this expression, the denominators are (m - 3) and (m + 1). We exclude 3 and -1 from the values of m because these values would make the denominator equal to zero.
Thus, the rational expression with non-permissible values of 3 and -1 is:
f(m) = 1 / (m - 3)(m + 1)
To create a rational expression with non-permissible values of 3 and -1, we need to include those values in the denominator of the expression.
We can create the rational expression by dividing two polynomials. Let's consider the denominator to be the product of two factors:
(x - 3)(x + 1)
This ensures that the expression becomes undefined when x = 3 or x = -1.
Now, we can choose any polynomial for the numerator. Let's use the simplest form, a constant:
m
Putting it all together, the rational expression with non-permissible values of 3 and -1 is:
m / ((x - 3)(x + 1))