if the sum of three consecutive positive number is 315. What is the numbers?
x+(x+1)+(x+2) = 315
3x + 3 = 315
X = 104
x+1 = 105
x+2 = 106.
a = first number
b = second number = a + 1
c = third number = b + 1 = a + 1 + 1 = a + 2
a + b + c = 315
a + a + 1 + a + a + 2 = 315
3 a + 3 = 315
Subtract 3 to both sides
3 a = 312
Divide both sides by 3
a = 104
b = a + 1 = 105 + 1 = 105
c = a + 2 = 104 + 2 = 106
104 + 105 + 106 = 315
Let's assume the first number is "x".
Since the numbers are consecutive, the second number will be "x + 1" and the third number will be "x + 2".
The sum of these three numbers is given as 315:
x + (x + 1) + (x + 2) = 315
Now, let's simplify the equation:
3x + 3 = 315
Subtract 3 from both sides of the equation:
3x = 315 - 3
3x = 312
Divide both sides of the equation by 3:
x = 312 / 3
x = 104
So, the first number is 104.
The second number is x + 1 = 104 + 1 = 105.
The third number is x + 2 = 104 + 2 = 106.
Therefore, the three consecutive positive numbers are 104, 105, and 106.
To find the three consecutive positive numbers whose sum is 315, we can define the numbers as x, x+1, and x+2. Adding these numbers together, we get the equation:
x + (x+1) + (x+2) = 315
Simplifying the equation, we have:
3x + 3 = 315
Subtracting 3 from both sides, we get:
3x = 312
Dividing both sides by 3, we find:
x = 104
So, the three consecutive positive numbers are 104, 105, and 106.