Abeba walks to school.she walkps 1km im 15 minutes.she meets her friend makeda - they talk for 5 minutes and then carry on walking to school.they walk 800 m in 10 minutes.drpaw a displacement-time graph to show abeba's journey to school.what was the average velocity of abeba's journy?give your answer in m/s.when was abebla's walking the faster?explain your answer.
Abeba walked 1.8 km in 1/2 hr = 3.6 km/hr
Makeda walked 0.8km in 1/4 hr = 3.2 km/hr (if you start timing when she meets Abeba)
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To draw a displacement-time graph for Abeba's journey to school, we need to plot the displacement (in meters) on the y-axis and the time (in minutes) on the x-axis. We will divide the journey into two parts: the first part when Abeba walks alone for 15 minutes, and the second part when she walks with her friend for 10 minutes.
For the first part of the journey, Abeba walks 1 km in 15 minutes, which is equivalent to 1000 meters in 15 minutes. To calculate the average velocity for this part, we can use the formula:
Average velocity = displacement / time
Displacement = 1000 meters (since Abeba walks 1 km)
Time = 15 minutes
Average velocity = 1000 meters / 15 minutes = 66.67 meters/minute
Now, let's plot this on the graph. At 15 minutes, the displacement will be 1000 meters.
For the second part of her journey, Abeba and Makeda walk 800 meters in 10 minutes. Again, we calculate the average velocity:
Average velocity = displacement / time
Displacement = 800 meters
Time = 10 minutes
Average velocity = 800 meters / 10 minutes = 80 meters/minute
Plot this on the graph, starting from 20 minutes with a displacement of 1000 meters (the end point of the first part) and going to 30 minutes with a displacement of 1800 meters (adding the 800-meter displacement from the second part).
To find the average velocity for the entire journey, we need to add up the total displacement and total time.
Total displacement = 1800 meters (from the end point of the second part)
Total time = 25 minutes (15 minutes from the first part + 10 minutes from the second part)
Average velocity = total displacement / total time
Average velocity = 1800 meters / 25 minutes = 72 meters/minute
To convert this to m/s, we need to divide by 60 (since there are 60 seconds in a minute):
Average velocity = 72 meters/minute / 60 = 1.2 meters/second
Therefore, the average velocity of Abeba's journey to school is 1.2 m/s.
To determine when Abeba was walking faster, we can compare the slopes of the two parts on the graph. The steeper the slope, the faster she was walking.
In this case, we can see that the slope of the second part (800 meters in 10 minutes) is steeper than the slope of the first part (1000 meters in 15 minutes). This means that Abeba was walking faster during the second part of her journey when she was with her friend.
I hope this answers your question and explains the process of finding the average velocity and determining when Abeba was walking faster.