Wine is approximately 12% ethanol (CH3CH2OH) by volume. Ethanol has a molar mass of
46.06 g/mol and a density 0.789 g/mL. How many moles of ethanol are present in a 750-mL
bottle of wine?
12% of 750mL = 90mL
90mL * 0.789g/mL * 1mol/46.06g = 1.54 mol
12% v/v means 12 mL ethanol in 100 mL total liquid so in 750 mL bottle of wine there is 12 x (750/100) = 90 mL of ethanol. How much does that weigh? That's 90 mL x 0.789 g/mL = 71 g.
mol = grams/molar mass = 71/46.06 = ?
1.54 mole of ethanol
71gmol
Well, let's do some chemistry calculations while trying to keep the party atmosphere!
First, we need to find the mass of ethanol in the bottle. We know that the density of ethanol is 0.789 g/mL, so we can multiply it by the volume of the bottle (750 mL) to get the mass.
0.789 g/mL * 750 mL = 591.75 g
Now, we need to find the number of moles by dividing the mass of ethanol by its molar mass.
591.75 g / 46.06 g/mol = 12.84 moles
So, there are approximately 12.84 moles of ethanol in a 750 mL bottle of wine. That's enough to make anyone forget their troubles and have a good time! Cheers!
To find the number of moles of ethanol in a 750-mL bottle of wine, we need to consider the given concentration of ethanol and its density.
First, let's calculate the mass of ethanol in the wine:
Mass = Volume x Density
Mass = 750 mL x 0.789 g/mL
Next, let's convert the mass into moles:
Moles = Mass / Molar mass
Moles = (750 mL x 0.789 g/mL) / 46.06 g/mol
Therefore, the number of moles of ethanol in a 750-mL bottle of wine is given by (750 mL x 0.789 g/mL) / 46.06 g/mol.