A 1.4-kg block of ice is at a temperature of -10∘C. If 6200 J of thermal energy is added to the ice, what is its final temperature?
from google ...
... the specific heat of ice is 2.04kJ/kg/K and the latent heat of fusion is 335kJ/kg
6.2 kJ is not enough to heat the block to the melting point
specific heat * mass * Δt = 6.2 kJ
... solve for Δt
so I just solve 2.04 * 335 * = 6.2? im confused
correct --
2.04 * 335 * Δt = 6.2
solve for Δt and then add that to the -10°C starting point (since °C are the same as °K)
-- look at the units.
J/(kg * °K) * kg * °K = J