CaCO3(s) + 2HCl(aq) CaCl2(aq) + H2O (l) +CO2(g) What’s the spectator ion in this ?
CaCO3(s) + 2HCl(aq) CaCl2(aq) + H2O (l) +CO2(g)
The net ionic equation is [CO3]^2- + 2H^+ ==>H2O(l) + CO2(g)
So Ca^2+ and 2Cl^- are the spectator ions.
The spectator ion in this reaction is the bored spectator sitting in the back row, wondering why they even bothered showing up because they're not really participating at all. In other words, the spectator ion is the chloride ion (Cl-) that appears on both sides of the equation and doesn't undergo any changes. It's just there to watch all the action from the sidelines.
To determine the spectator ion in a chemical reaction, we need to identify the ions that do not undergo a chemical change and remain in solution throughout the reaction.
In the given reaction between calcium carbonate (CaCO3) and hydrochloric acid (HCl), the balanced equation is:
CaCO3(s) + 2HCl(aq) → CaCl2(aq) + H2O(l) + CO2(g)
From the equation, it is clear that the calcium chloride (CaCl2) is formed as a dissolved product in the aqueous solution. This means that Ca2+ and Cl- ions are both present in the reactants (HCl) and products (CaCl2).
On the other hand, the water (H2O) and carbon dioxide (CO2) are formed as a liquid and gas respectively, and they do not remain as ions in the solution.
Therefore, the spectator ion in this reaction is the Cl- ion.
To determine the spectator ion in a chemical reaction, you need to identify which ions remain unchanged throughout the reaction. In this case, the reaction involves the reaction of solid calcium carbonate (CaCO3) with hydrochloric acid (HCl) to form aqueous calcium chloride (CaCl2), water (H2O), and carbon dioxide gas (CO2).
The ionic equation for this reaction can be written as follows:
CaCO3(s) + 2H+(aq) + 2Cl-(aq) → Ca2+(aq) + 2Cl-(aq) + H2O(l) + CO2(g)
In this equation, the "Ca2+" and "2Cl-" ions are present on both sides of the reaction arrow and hence do not participate in the reaction. They remain unchanged and are called spectator ions.
Therefore, the spectator ion in this reaction is the chloride ion (Cl-).