Yolanda is 4 years younger than 3 times her daughter's age. The sum of their ages is greater than 88.
What is the youngest age Yolanda's daughter can be?
y = Yolanda's Age
d = Daughter's Age
y = 3d - 4
y + d > 88
y + d = 3d - 4 + d = 88
4d - 4 = 88
4d - 4 = 88
Daughter=x
Yolanda=3x-4
X+3x-4>88
X>88
To find the youngest age Yolanda's daughter can be, we need to analyze the given information.
Let's assume the daughter's age is "x." According to the problem, Yolanda is 4 years younger than 3 times her daughter's age. So, Yolanda's age can be expressed as 3x - 4.
The sum of their ages is greater than 88. This can be written as:
x + (3x - 4) > 88
Now we can solve this equation to find the youngest age for Yolanda's daughter.
Combining like terms, we have:
4x - 4 > 88
Adding 4 to both sides, we get:
4x > 92
Dividing both sides by 4, we have:
x > 23
Therefore, the youngest age Yolanda's daughter can be is 24.