For Fe2O3 + H2 --> 2Fe + 3H20

If you have 220 kg H20, how many kg of Fe2O3 did you have?

Sorry I meant: For Fe2O3 + 3H2 --> 2Fe + 3H20

If you have 220 kg H20, how many kg of Fe2O3 did you have?

Fe2O3 + 3H2 --> 2Fe + 3H20

mols H2O formed = 220,000 g/molar mass = estimated 12.
Convert to mols Fe2O3. That is 12 mols H2O x (1 mol Fe2O3/3 mols H2) = estimated 12 x 1/3 = about 4
Then grams Fe2O3 = mols x molar mass = ?
Then convert to kg.

To find the amount of Fe2O3, we need to use stoichiometry. Stoichiometry is the calculation of the quantities of reactants and products in a chemical equation.

In the balanced equation, the coefficient in front of Fe2O3 is 1, which means that 1 mole of Fe2O3 reacts with 3 moles of H2O to produce 3 moles of H2O.

To calculate the moles of H2O, we can use the molar mass of H2O, which is approximately 18 g/mol. To convert 220 kg of H2O to grams, we multiply by 1000 (to convert kg to grams) and then divide by the molar mass:

220 kg × 1000 g/kg = 220,000 g H2O

220,000 g H2O / 18 g/mol = 12,222.22 mol H2O

According to the stoichiometry, the molar ratio between Fe2O3 and H2O is 1:3. Therefore, the moles of Fe2O3 will be one-third of the moles of H2O:

12,222.22 mol H2O × (1 mol Fe2O3 / 3 mol H2O) = 4,074.07 mol Fe2O3

Now, we need to convert moles of Fe2O3 to kilograms. To do this, we need to multiply by the molar mass of Fe2O3, which is approximately 160 g/mol:

4,074.07 mol Fe2O3 × 160 g/mol = 651,853.12 g Fe2O3

To convert grams to kilograms, we divide by 1000:

651,853.12 g Fe2O3 / 1000 = 651.85 kg Fe2O3

Therefore, if you have 220 kg of H2O, you would have approximately 651.85 kg of Fe2O3.