The explicit form for a sequence is a n =4n-5 Write the first four terms in the sequence.
C. -9, -13, -17, -21, -25
An = -4n-5
To get the first five terms just put 1,2,3,4,5 in where there is n
Example
A(1) = -4(1)-5 = -9
Repeat this process for each number
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plug 1 thru 4 into the equation
a1 = (4 * 1) + 5
a2 = (4 * 2) + 5
etc.
A(2) =4(1)+5
Sure, here are the first four terms of the sequence:
a₁ = 4(1) - 5 = -1
a₂ = 4(2) - 5 = 3
a₃ = 4(3) - 5 = 7
a₄ = 4(4) - 5 = 11
So, the first four terms of the sequence are -1, 3, 7, and 11. They're like a rollercoaster ride, taking you on an emotional journey from negative to positive numbers! Enjoy the thrill!
To find the first four terms in the sequence with the explicit form aₙ = 4n - 5, we can substitute the values of n into the equation and calculate the corresponding terms.
Let's plug in the values of n from 1 to 4, one at a time, into the equation aₙ = 4n - 5:
For n = 1:
a₁ = 4(1) - 5
a₁ = 4 - 5
a₁ = -1
For n = 2:
a₂ = 4(2) - 5
a₂ = 8 - 5
a₂ = 3
For n = 3:
a₃ = 4(3) - 5
a₃ = 12 - 5
a₃ = 7
For n = 4:
a₄ = 4(4) - 5
a₄ = 16 - 5
a₄ = 11
Therefore, the first four terms in the sequence are: -1, 3, 7, 11.