Find all solutions of θ in radians where (0 ≤ θ < 2π) given: 1+cot^2x-cot^4x=1
The first part is just Algebra I. Subtract 1 from both sides and factor to get
cot^2x(cot^2x-1) = 0
cotx = 0
cotx = ±1
Not so hard now, I hope.
cot^2x(cot^2x-1) = 0
cotx = 0
cotx = ±1
Not so hard now, I hope.