what is the concentration of ions in 1.2 M aluminum nitrate solution

Al(NO3)3

I count four ions )(one Al, three nitrate), so the conc of ions will be 4 times the concentration.

To find the concentration of ions in a solution of aluminum nitrate, you'll first need to identify the number of ions present in one molecule of aluminum nitrate. In this case, aluminum nitrate (Al(NO3)3) dissociates into one aluminum ion (Al3+) and three nitrate ions (NO3-) when it is dissolved in water.

Next, you need to consider the molarity (M) of the solution, which is given as 1.2 M. The molarity tells you the number of moles of solute (in this case, aluminum nitrate) present per liter of solution.

Since we are interested in finding the concentration of ions, you can multiply the molarity of the aluminum nitrate solution by the number of ions formed when it dissociates. In this case, you have one aluminum ion and three nitrate ions, so there are a total of four ions produced.

Therefore, the concentration of ions in the 1.2 M aluminum nitrate solution would be 4 times the molarity, which is:

Concentration of ions = 4 * 1.2 M = 4.8 M

So, the concentration of ions in the 1.2 M aluminum nitrate solution is 4.8 M.