The line of symmetry of the parabola whose equation is y = ax2 - 4x + 3 is x = -2. What is the value of "a"?
-2
-1/2
-1
for the axis of symmetry ... x = -b / 2a
-2 = - -4 / 2a ... -4 a = 4
To find the value of "a" in the equation y = ax^2 - 4x + 3, we know that the line of symmetry of the parabola is given by the equation x = -b/2a. Here, we have b = -4.
Plugging -b/2a as x = -2 into the equation gives us:
-2 = -(-4) / 2a
-2 = 4 / 2a
-2 = 2 / a
Now, we can cross-multiply:
-2a = 2
a = 2 / -2
a = -1
So, the value of "a" is -1.