A 6v battery battery internal resistance 0.5 ohm connected to three resistors of values 3 ohm,4 ohm & 5 ohm.calculate the current in each resistor, the p.d across the 3 ohm,and across the 5 & 4 ohm which are in parallel

Ohm my, what a shocking question! Let me help you with some electrifying answers.

To calculate the current in each resistor, we first need to calculate the total resistance of the circuit. Since the resistors 4 ohm and 5 ohm are in parallel, we can calculate their combined resistance using the formula:

1/Total Resistance = 1/4 ohm + 1/5 ohm

1/Total Resistance = 9/20 ohm

Total Resistance = 20/9 ohm

Now, let's calculate the total current using Ohm's Law: Current = Voltage / Resistance

Total Current = 6 volts / (0.5 ohm + (20/9) ohm + 3 ohm)

Total Current = 6 volts / (0.5 ohm + 20/9 ohm + 3 ohm)

Total Current = 6 volts / (1/2 ohm + 20/9 ohm + 3 ohm)

Total Current = 6 volts / (45/18 ohm + 40/18 ohm + 54/18 ohm)

Total Current = 6 volts / (139/18 ohm)

Now, to find the current in each resistor, we can use the formula:

Current in each resistor = Total Current * (Resistance of each resistor / Total Resistance)

Current in the 3 ohm resistor = Total Current * (3 ohm / 20/9 ohm)

Current in the 4 ohm and 5 ohm resistors = Total Current * [(4 ohm + 5 ohm) / 20/9 ohm]

Now go ahead and calculate those currents. Just be careful not to get too zapped by the answers!

To find the current in each resistor, we can use Ohm's Law (V = IR), where V is the voltage, I is the current, and R is the resistance.

First, we need to calculate the total resistance of the parallel resistors (4 ohm and 5 ohm). The formula for calculating the total resistance of two parallel resistors is given by:

1/𝑅𝑡 = 1/𝑅1 + 1/𝑅2

Where 𝑅𝑡 is the total resistance, 𝑅1 is the resistance of the first resistor, and 𝑅2 is the resistance of the second resistor.

Let's calculate the total resistance of the 4 ohm and 5 ohm resistors:

1/𝑅𝑡 = 1/4 + 1/5
1/𝑅𝑡 = 5/20 + 4/20
1/𝑅𝑡 = 9/20
𝑅𝑡 = 20/9 ≈ 2.22 ohm

Now, we can find the current in each resistor.

1. Current in the 3 ohm resistor (𝑅1):
Using Ohm's Law:
𝑉 = 𝐼 × 𝑅
6V = 𝐼 × 3 ohm
𝐼 = 6V / 3 ohm
𝐼 = 2A

2. Current in the parallel resistors (4 ohm and 5 ohm):
Using Ohm's Law:
𝑉 = 𝐼 × 𝑅
6V = 𝐼 × 2.22 ohm
𝐼 = 6V / 2.22 ohm
𝐼 ≈ 2.70A

Now, let's calculate the voltage across the 3 ohm resistor, which is the same as the total voltage of the circuit.

Using Ohm's Law:
𝑉 = 𝐼 × 𝑅
𝑉 = 2A × 3 ohm
𝑉 = 6V

Finally, let's calculate the voltage across the parallel resistors (4 ohm and 5 ohm), which is the same as the total voltage of the circuit.

Using Ohm's Law:
𝑉 = 𝐼 × 𝑅
𝑉 = 2.70A × 2.22 ohm
𝑉 ≈ 6V

Therefore, the current in the 3 ohm resistor is 2A, the current in the parallel resistors (4 ohm and 5 ohm) is approximately 2.70A, the voltage across the 3 ohm resistor is 6V, and the voltage across the parallel resistors (4 ohm and 5 ohm) is approximately 6V.

To calculate the current in each resistor and the potential difference (p.d.) across the resistors, we can use Ohm's Law and apply Kirchhoff's Circuit Laws. Here's how you can solve the problem step by step:

Step 1: Calculate the total resistance in the circuit:
Since the 5 ohm and 4 ohm resistors are in parallel, we can calculate their equivalent resistance using the formula:

1/Req = 1/R1 + 1/R2

1/Req = 1/4 + 1/5
1/Req = 0.25 + 0.2
1/Req = 0.45

Req = 1 / 0.45
Req = 2.222 ohms

The total resistance in the circuit is the sum of the 3 ohm resistor and the equivalent resistance of the 4 ohm and 5 ohm resistors:

Total Resistance (RT) = 3 + Req
RT = 3 + 2.222
RT = 5.222 ohms

Step 2: Calculate the total current in the circuit:
Using Ohm's Law (V = IR), we can find the total current (I) flowing through the circuit:

I = V / R
I = 6V / 5.222 ohms
I ≈ 1.148 A (rounded to three decimal places)

Step 3: Calculate the current in each resistor:
Since the resistors are connected in series, the current flowing through each resistor will be the same as the total current (I = 1.148 A).

Current in the 3 ohm resistor (I3) = 1.148 A
Current in the 4 ohm resistor (I4) = 1.148 A
Current in the 5 ohm resistor (I5) = 1.148 A

Step 4: Calculate the potential difference across the 3 ohm resistor (V3):
Using Ohm's Law (V = IR), we can find the potential difference (V3) across the 3 ohm resistor:

V3 = I3 * R3
V3 = 1.148 A * 3 ohms
V3 ≈ 3.444 V (rounded to three decimal places)

Step 5: Calculate the potential difference across the parallel combination of the 4 ohm and 5 ohm resistors (V45):
Since the resistors are in parallel, they have the same potential difference (V45) as the battery voltage (6V).

V45 = 6 V

So, the current in each resistor is approximately 1.148 A, the potential difference across the 3 ohm resistor is approximately 3.444 V, and the potential difference across the 4 ohm and 5 ohm resistors (in parallel) is equal to the battery voltage of 6V.