Question

In two or more complete sentences, compare the number of -intercepts in the graph of f(x)=x^2 to the number of x-intercepts in the graph of g(x)=-x^2 - 5

Answer 1

x^2 hits the x axis just once, at x = y = 0

now if y = -x^2 - 5
then for y = 0 you have
x^2 = -5
x = +/- i sqrt 5
In other words the roots are imaginary and it NEVER hits the axis
HOWEVER if you have a typo and mean:
g(x) = x^2 -5
then
x^2 = 5 for y = g(x) = 0
and x = + or - sqrt 5, two roots

Answer 2

[AI-generated answer — Explain Bot]

To find the number of x-intercepts in the graph of f(x)=x^2, we need to set f(x) equal to zero and solve for x. The resulting equation is x^2 = 0, which only has one solution: x = 0. Therefore, the graph of f(x)=x^2 has one x-intercept. On the other hand, to find the number of x-intercepts in the graph of g(x)=-x^2 - 5, we set g(x) equal to zero and solve: -x^2 - 5 = 0. This equation has no real solutions, meaning the graph of g(x) has no x-intercepts. Thus, the graph of f(x)=x^2 has 1 x-intercept, while the graph of g(x)=-x^2 - 5 has no x-intercepts.