A body of mass 2kg moving with velocity of 6m/s collides with a stationary object of mass 0.5kg. If the two bodies move together after impact, calculate their common velocity.
conserve momentum
2*6 = 2.5v
Answer the question i ask not yur
To calculate the common velocity of the two bodies after the impact, we can use the principle of conservation of momentum.
The momentum before the collision is equal to the momentum after the collision.
The momentum (p) of an object is calculated by multiplying its mass (m) by its velocity (v): p = m * v.
Before the collision, the momentum of the first body is:
p1_initial = m1 * v1
= 2 kg * 6 m/s
= 12 kg*m/s
The momentum of the second body is initially zero since it is stationary:
p2_initial = m2 * v2
= 0.5 kg * 0 m/s
= 0 kg*m/s
The total momentum before the collision is the sum of the individual momenta:
P_initial = p1_initial + p2_initial
= 12 kg*m/s + 0 kg*m/s
= 12 kg*m/s
After the collision, the two bodies move together with a common velocity v_common.
The momentum of the combined system after the collision is:
P_final = (m1 + m2) * v_common
Since the momentum is conserved, P_initial = P_final.
Therefore, we can equate the two expressions for momentum and solve for v_common:
12 kg*m/s = (2 kg + 0.5 kg) * v_common
12 kg*m/s = 2.5 kg * v_common
v_common = (12 kg*m/s) / (2.5 kg)
≈ 4.8 m/s
Hence, the common velocity of the two bodies after the impact is approximately 4.8 m/s.
To calculate the common velocity of the two bodies after the collision, we can apply the principle of conservation of momentum. According to this principle, the total momentum of an isolated system remains constant before and after a collision.
The momentum of an object is given by the product of its mass and velocity. Therefore, the initial momentum of the first body (moving with a velocity of 6 m/s) can be calculated as:
Momentum of the first body = mass × velocity = 2 kg × 6 m/s = 12 kg⋅m/s
Since the second object is stationary, its initial momentum is zero.
After the collision, the two objects will move together as a single entity with a common velocity (let's call it V). The final momentum of the system can be expressed as:
Final momentum of the system = (total mass) × (common velocity)
In this case, the total mass of the system is the sum of the masses of the two bodies:
Total mass = mass of the first body + mass of the second body = 2 kg + 0.5 kg = 2.5 kg
Applying the principle of conservation of momentum, we can equate the initial and final momentum:
Initial momentum = Final momentum
12 kg⋅m/s = (2.5 kg) × V
Now we can solve for V:
V = 12 kg⋅m/s / 2.5 kg
V = 4.8 m/s
Therefore, the common velocity of the two bodies after the collision is 4.8 m/s.