A projectile is launched with a speed Vo at an angle 45° with horizontal find ratio of its minimum and maximum K.E ?

neglecting air resistance ... max K.E. is at launch ... 1/2 * m * Vo^2

min K.E. is at max height
... zero vertical velocity ... horizontal velocity equals ... Vo cos(45º)
... 1/2 * m * (Vo * √2 / 2)^2 = m * Vo^2 / 4

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