Calculate the number of moles of H2O formed when 0.200 mole of Ba(OH)2 is treated with 0.500 mol of HClO3 according to the chemical reaction shown below.
Ba(OH)2 + 2 HClO3 ----> Ba(ClO3)2 + 2 H2O
0.2 mole Ba(OH)2 will use 0.4 moles of HClO3 and produce 0.4 moles of H2O
To calculate the number of moles of H2O formed, we can use the stoichiometry of the balanced chemical equation.
From the balanced chemical equation:
1 mole of Ba(OH)2 reacts with 2 moles of HClO3 to produce 2 moles of H2O.
Given:
- 0.200 mole of Ba(OH)2
- 0.500 mole of HClO3
Based on the stoichiometry, we know that 0.200 mole of Ba(OH)2 will react with 0.400 mole of HClO3 to form 0.400 mole of H2O (since the ratio is 1:2).
Therefore, the number of moles of H2O formed when 0.200 mole of Ba(OH)2 is treated with 0.500 mole of HClO3 is 0.400 mole.
To calculate the number of moles of H2O formed, we need to use the given amounts of reactants and the stoichiometric coefficients in the balanced chemical equation.
1. Start by writing down the balanced chemical equation:
Ba(OH)2 + 2 HClO3 ----> Ba(ClO3)2 + 2 H2O
2. Identify the stoichiometric coefficients for Ba(OH)2 and H2O. In this case, the stoichiometric coefficient for H2O is 2.
3. Use the stoichiometric coefficients to convert the given mole of Ba(OH)2 to moles of H2O.
Given: 0.200 mol Ba(OH)2
Stoichiometric coefficient ratio: Ba(OH)2 to H2O (1:2)
0.200 mol Ba(OH)2 * (2 mol H2O / 1 mol Ba(OH)2) = 0.400 mol H2O
Therefore, when 0.200 mole of Ba(OH)2 is treated with 0.500 mol of HClO3, 0.400 mole of H2O is formed.