You have an ideal gas in an insulated container. The volume of the container increases from 10 m3 to 20 m3 under a constant pressure of 50. × 105 Pa. What was the work done on the gas?
1- 500.0 K J
2- 5000 kJ
3- 50000KJ
4- 10000 KJ
5- 100000 k
To calculate the work done on the gas, you can use the formula:
Work = Pressure × Change in Volume
Given:
Initial volume, V1 = 10 m^3
Final volume, V2 = 20 m^3
Pressure, P = 50 × 10^5 Pa
Now, calculate the change in volume:
Change in Volume = V2 - V1
= 20 m^3 - 10 m^3
= 10 m^3
Substitute the values into the work formula:
Work = Pressure × Change in Volume
= 50 × 10^5 Pa × 10 m^3
= 500 × 10^5 J
Since the answer options are given in kilo-Joules (kJ), you need to convert the answer to kJ by dividing by 1000:
Work = 500 × 10^5 J ÷ 1000
= 500 × 10^2 kJ
= 50000 kJ
Therefore, the work done on the gas is 50000 kJ, so the correct answer is option 3.