How many molecules of glycerol (C₃H₈O₃; molecular mass = 92) would be present in 1 L of a 1 M glycerol solution?
1M means 1 mole per liter
1 mole of glycerol is 92 grams
To calculate the number of molecules of glycerol in a 1 L solution, we need to use Avogadro's number (6.022 x 10^23) and the molarity (1 M).
1 M glycerol solution means there is 1 mole of glycerol per liter of solution.
First, let's calculate the number of moles of glycerol in 1 L of the solution.
Number of moles = Molarity * Volume
Number of moles = 1 M * 1 L
Number of moles = 1 mole
Now, we can calculate the number of molecules using Avogadro's number.
Number of molecules = Number of moles * Avogadro's number
Number of molecules = 1 mole * 6.022 x 10^23
Number of molecules = 6.022 x 10^23 molecules
Therefore, there would be approximately 6.022 x 10^23 molecules of glycerol in 1 L of a 1 M glycerol solution.
To determine the number of molecules of glycerol in a 1 L, 1 M solution, we can use Avogadro's number and the definition of molarity.
First, let's calculate the number of moles of glycerol in 1 L of a 1 M solution using the formula:
moles = molarity × volume
moles = 1 M × 1 L = 1 mol
Since 1 mole of any substance contains Avogadro's number of particles, which is approximately 6.022 × 10^23, we can calculate the number of molecules of glycerol using:
number of molecules = moles × Avogadro's number
number of molecules = 1 mol × 6.022 × 10^23 molecules/mol
number of molecules = 6.022 × 10^23 molecules
Therefore, there would be approximately 6.022 × 10^23 molecules of glycerol in 1 L of a 1 M glycerol solution.