# calculus

The base of a solid is a circle of
Find the exact volume of this solid if the cross sections perpendicular to a given axis are equilateral right triangles.

I have the area of the triangle (1/2bh) to be equal to 2sqrt(12)
(1/2 * 4 * sqrt12)

I don't know what to do next. If someone knows, I'd be very thankful.

there are like triangles that have vertical bases. They run parallel to the y-axis. The triangles form 2 triangles each that are symmetric to the x-axis.

The equation of the circle is:
x^2 + y^2 = 16

Thanks!

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1.rectangular prism
2.pyramid
3. BE and DF
4.first one
5.first one
6.rectangular prism
7.cube
8.2,280 cm^2
9.302 m^2
10.715 in^3
11.216 ft^3
12.151 in.^3
13.147 yd^3
14.10 cm
15.16 cm
16. 9 ft
17.810 cm^3
18. 201 m^2
19. 268^3

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posted by wow

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