calculus

The base of a solid is a circle of
radius = 4
Find the exact volume of this solid if the cross sections perpendicular to a given axis are equilateral right triangles.

I have the area of the triangle (1/2bh) to be equal to 2sqrt(12)
(1/2 * 4 * sqrt12)

I don't know what to do next. If someone knows, I'd be very thankful.

there are like triangles that have vertical bases. They run parallel to the y-axis. The triangles form 2 triangles each that are symmetric to the x-axis.

The equation of the circle is:
x^2 + y^2 = 16

Thanks!

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asked by mark
  1. answer are
    1.rectangular prism
    2.pyramid
    3. BE and DF
    4.first one
    5.first one
    6.rectangular prism
    7.cube
    8.2,280 cm^2
    9.302 m^2
    10.715 in^3
    11.216 ft^3
    12.151 in.^3
    13.147 yd^3
    14.10 cm
    15.16 cm
    16. 9 ft
    17.810 cm^3
    18. 201 m^2
    19. 268^3

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    posted by wow

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