The specific heat capacity of the lava is 1600 J kg^-1 degres celsuis ^-1. when all the erupted lava cools from the eruption temperature of 1050 degrees Celsius to 15 degrees celsius, the heat released is 2 x 10 ^15 J.
calculate a value for the total mass of lava that erupted. give your answer in scientific notation.
plzzz some one help meeee....
i posted this question before and i still don't get how u work out the mass
Use the equation
(Heat release) = Mass x (specific heat) x (change in temperature)
Rearrange it algebraically to solve for the mass.
is this right ...in that case ..or where am going wrong !!
1600 J kg -1 °C -1 x 2 x 10 15 J x 1035 °C = 3.312 x 10 21 kgs
To calculate the total mass of lava that erupted, you need to rearrange the equation correctly and include the correct values for the specific heat capacity and the change in temperature.
The equation you should use is:
Heat release = Mass x specific heat x change in temperature
Rearranging the equation to solve for the mass, you get:
Mass = Heat release / (specific heat x change in temperature)
Now, substitute the given values into the equation:
Mass = (2 x 10^15 J) / (1600 J kg^-1 °C^-1 x (1050 °C - 15 °C))
Mass = (2 x 10^15 J) / (1600 J kg^-1 °C^-1 x 1035 °C)
Mass = (2 x 10^15 J) / (1664000 J kg^-1 °C^-1)
Mass ≈ 1.20 x 10^9 kg (in scientific notation)
Therefore, the total mass of lava that erupted is approximately 1.20 x 10^9 kg.