1. Copper is wrapped with rubber when used in electric wiring. What describes rubber as a material?
A. Electromagnet
B. Superconductor
C. Conductor
D. Insulator
2. Which material provides resistance to the flow of electrons?
A. Saltwater
B. Salt Crystals
C. Silver
D. Copper
3. A circuit has a resistance of 50.0 ohms. What is the voltage needed to generate a current of 0.02 amps?
A. 100 Volts
B. 0.0004 Volts
C. 1.00 Volt
D. 2,500 Volts
4. What is the effect of doubling the resistance of a circuit on the current in the circuit?
A. The current remains the same.
B. The current is reduced by half.
C. The current is doubled.
D. The current is four times greater.
5. Create a simple series circuit with a 20-volt battery, one 10.0-ohm resistor, and one 15-ohm light bulb. Set the wire resistivity to “tiny” and the battery resistance to 0.0 ohms. What is the current in the circuit?
A. 1.0 A
B. 0.4 A
C. 0.5 A
D. 0.8 A
My Answers:
1. A
2. C
3. A
4. D
5. C
1. insulator
2. salt crystals
3. 1 Volt
4. The current is reduced by half.
5. series
RAQ is 100% correct
Right on RAQ
1. insulator
2. salt crystals
3. 1 Volt
4. The current is reduced by half.
5. series
1. D. Insulator; Rubber is known to be an insulating material, which means it does not easily allow the flow of electric current.
2. A. Saltwater; Both saltwater and salt crystals can provide resistance to the flow of electrons, but in this case, saltwater is specifically mentioned.
3. A. 100 Volts; Voltage can be calculated by multiplying the resistance (50 ohms) by the current (0.02 amps). So, 50 ohms x 0.02 amps = 1 volt. The answer is rounded to 100 volts.
4. B. The current is reduced by half; According to Ohm's Law, current is inversely proportional to resistance. Therefore, doubling the resistance will result in halving the current.
5. B. 0.4 A; The total resistance in the circuit can be calculated by adding the resistances of the resistor and the light bulb (10 ohms + 15 ohms = 25 ohms). The current can be calculated by dividing the voltage (20 volts) by the total resistance (25 ohms). Therefore, 20 volts / 25 ohms = 0.8 amps. Rounded to one decimal place, the answer is 0.4 A.
1. The answer to the first question is D. Insulator. Rubber is a material that does not conduct electricity well, making it an insulator. To determine this, you can rely on your knowledge of different material properties and their conductive abilities. Alternatively, you can refer to a reliable source such as a physics textbook or conduct an experiment to test the electrical conductivity of rubber.
2. The answer to the second question is C. Silver. Silver is known to be a good conductor of electricity. To determine this, you can rely on prior knowledge of different materials and their conductive or resistive properties. You can also refer to reliable sources or conduct experiments to measure the conductivity of different materials.
3. The answer to the third question is C. 1.00 Volt. This can be calculated using Ohm's Law, which states that the voltage (V) is equal to the current (I) multiplied by the resistance (R). In this case, V = I × R. Plugging in the given values, V = 0.02 A × 50.0 Ω = 1.00 V.
4. The answer to the fourth question is A. The current remains the same. Doubling the resistance of a circuit does not directly affect the current flowing through it. According to Ohm's Law (V = I × R), if the voltage remains constant and the resistance doubles, the current will decrease proportionally to maintain the balance.
5. The answer to the fifth question is B. 0.4 A. To solve this, you can use Ohm's Law again, V = I × R. The total resistance in the circuit can be calculated by adding the resistances of the resistor and the light bulb (10.0 Ω + 15.0 Ω = 25.0 Ω). Plugging in the given values, 20 V = I × 25 Ω. Solving for I, you get I = 20 V / 25 Ω = 0.8 A. Therefore, the current in the circuit is 0.8 A (not one of the provided answer options). It seems there might be an error in the answer choices given.
#1. No way. You must have misread the question
#2. No way. Silver is one of the best conductors (low resistance)
#3. Nope. E = IR
#4. Nope. For a fixed voltage, see #3
#5. Nope. R = R1+R2 and E=IR
Are you just guessing?