When an aqueous solutions of ammonium sulfate is combined with an aqueous solution of lead(II) chloride, a white precipitate forms.
Find the net equation.
[SO4]^2-(aq) + Pb^2+(aq) ==> PbSO4(s)
Note: PbCl2 is not all that soluble. PbSO4 is more insoluble than PbCl2.
To find the net equation, we need to first write the balanced chemical equation for the reaction between ammonium sulfate (NH4)2SO4 and lead(II) chloride PbCl2.
The chemical formulas for the reactants are:
Ammonium sulfate: (NH4)2SO4
Lead(II) chloride: PbCl2
The balanced equation for the reaction can be written as follows:
(NH4)2SO4 + PbCl2 → 2NH4Cl + PbSO4
In this reaction, the ammonium sulfate reacts with lead(II) chloride to produce ammonium chloride (NH4Cl) and lead(II) sulfate (PbSO4) as the products.
Therefore, the net equation for the reaction is:
(NH4)2SO4 + PbCl2 → 2NH4Cl + PbSO4
To find the net equation for the reaction between ammonium sulfate and lead(II) chloride, we need to determine the formulas of the products formed and balance the equation. Let's break down the process step by step:
1. Write the balanced molecular equation:
Ammonium sulfate is represented by the formula (NH4)2SO4, and lead(II) chloride is represented by PbCl2. When they react, they form ammonium chloride (NH4Cl) and lead(II) sulfate (PbSO4).
(NH4)2SO4 + PbCl2 → 2NH4Cl + PbSO4
2. Check solubility rules:
To determine if a precipitate is formed, you need to consider the solubility of the products. According to the solubility rules, ammonium chloride (NH4Cl) is soluble, meaning it remains in solution, while lead(II) sulfate (PbSO4) is insoluble and forms a solid precipitate.
Therefore, the net equation for the reaction is:
(NH4)2SO4 + PbCl2 → PbSO4 ↓ + 2NH4Cl
The ↓ symbol indicates the formation of a precipitate.