At a local fitness center, members pay aa $12 membership fee and $3 for each aerobics class. Nonmembers pay $5 for each aerobics class. For what number of aerobics classes will the cost for members and nonmembers be the same?
12+3x = 5x
To find the number of aerobics classes where the cost for members and nonmembers will be the same, let's set up an equation:
Cost for members = Cost for nonmembers
Let's say the number of aerobics classes is represented by 'x'.
For members, the cost would be: $12 (membership fee) + $3 (cost per class) * x (number of classes)
So, for members, the equation is: 12 + 3x.
For nonmembers, the cost would be: $5 (cost per class) * x (number of classes)
So, for nonmembers, the equation is: 5x.
Now, let's equate the two equations and solve for x:
12 + 3x = 5x
Subtract 3x from both sides:
12 = 2x
Divide both sides by 2:
x = 6
Therefore, the cost for members and nonmembers will be the same when there are 6 aerobics classes.
To find the number of aerobics classes at which the cost for members and nonmembers is the same, we need to set up and solve an equation.
Let's represent the number of aerobics classes as "x".
For members, the cost is the sum of the membership fee ($12) and the cost per class ($3x), which gives us the equation:
Cost for members = 12 + 3x
For nonmembers, the cost is simply the cost per class ($5x), which gives us the equation:
Cost for nonmembers = 5x
To find the number of classes at which the costs are the same, we set up an equation and solve for x:
12 + 3x = 5x
Simplifying the equation, we subtract 3x from both sides:
12 = 2x
Next, we divide both sides by 2:
x = 6
Therefore, the cost for members and nonmembers will be the same when the number of aerobics classes is 6.