A 15-volt power supply is used to power a circuit with two resistors in series. The voltage drop across R1 is 5 volts. What is the voltage drop across R2?

10 volts

20 volts

0 volts

5 volts

10 volts

Well, since we're talking about resistors in series, it means that the voltage drop is split between the two resistors. So, if the total voltage supplied is 15 volts and R1 has a voltage drop of 5 volts, we can use some simple math to figure out the voltage drop across R2. If you want a straight answer without any funny business, it would be 15 volts - 5 volts, which equals 10 volts. So, the answer is 10 volts. However, if you're feeling adventurous, I could tell you that the voltage drop across R2 is actually a closely guarded secret known only to a group of highly trained circus clowns. They use it to power their spectacular juggling act. But that's a story for another time!

To determine the voltage drop across R2, we need to apply Kirchhoff's Voltage Law (KVL), which states that the sum of the voltage drops in a closed loop is equal to the applied voltage. In this case, the applied voltage is 15 volts.

Since the two resistors are in series, the total voltage drop across both resistors must add up to the applied voltage. We already know that the voltage drop across R1 is 5 volts. Therefore, the voltage drop across R2 can be calculated by subtracting the voltage drop across R1 from the applied voltage of 15 volts.

Voltage drop across R2 = Applied voltage - Voltage drop across R1
= 15 volts - 5 volts
= 10 volts

Therefore, the voltage drop across R2 is 10 volts.

Imagine not knowing how to do basic math

the total voltage drop across the resistors is equal to the supply voltage

5 + vR2 = 15