Which of the following solutions of strong electrolytes contains the largest # of moles of chloride ions: 100.0 mL of 0.30 M AlCl3, 50.0 mL of0.60 M MgCl2, or 200.0 mL of 0.40M NaCl? What formula is used?
I am not familiar with the ^- symbol in the equation after # Cl. Is that referring to the power, such as Cl3?
Nevermind, I figured it out from the original formula you gave me and got the correct answer. Thanks for your help!!
right. We don't (or can't) do exponents right so we write the caret(^) which is used in computer programming to indicate an exponent. And of course # stands for number.
To determine which solution contains the largest number of moles of chloride ions, we need to calculate the moles of chloride ions for each solution and compare them.
To calculate the moles of chloride ions, we can use the formula:
moles = concentration (in mol/L) x volume (in L)
Let's calculate the moles of chloride ions for each solution:
1. 100.0 mL of 0.30 M AlCl3:
- Concentration = 0.30 mol/L
- Volume = 100.0 mL = 100.0 mL x (1 L/1000 mL) = 0.100 L
- Moles of chloride ions = 0.30 mol/L x 0.100 L = 0.030 moles
2. 50.0 mL of 0.60 M MgCl2:
- Concentration = 0.60 mol/L
- Volume = 50.0 mL = 50.0 mL x (1 L/1000 mL) = 0.050 L
- Moles of chloride ions = 0.60 mol/L x 0.050 L = 0.030 moles
3. 200.0 mL of 0.40 M NaCl:
- Concentration = 0.40 mol/L
- Volume = 200.0 mL = 200.0 mL x (1 L/1000 mL) = 0.200 L
- Moles of chloride ions = 0.40 mol/L x 0.200 L = 0.080 moles
Comparing the moles of chloride ions for each solution, we find that 200.0 mL of 0.40 M NaCl contains the largest number of moles of chloride ions, with 0.080 moles.
Therefore, the solution with 200.0 mL of 0.40 M NaCl contains the largest number of moles of chloride ions among the given options.