PLS HELP!!!
If a car travels at a constant rate of speed, the distance that it travels varies directly as time. If a car travels 75 miles in 2.5 hours, it will travel 110 feet in 2.5 seconds.
a. Find the constant of variation in miles per hour
b. Draw a graph that compares the distance that the car travels in miles to the number of hours traveled. Let the horizontal axis represent minutes and the vertical axis represents characters.
c. Find the constant of variation in feet per second.
d. Draw a graph that compares the distance the car travels in feet to the number of seconds traveled.
what's the question?
wdym
y = kx
for mi/hr, k=75/2.5 = 30
similarly for ft/s
Incidentally, 60 mi/hr = 88 ft/s, so these two speeds are not the same!
a. To find the constant of variation in miles per hour, we need to use the given information that the car travels 75 miles in 2.5 hours. The formula for direct variation is distance = k * time, where k is the constant of variation. Rearranging the formula and substituting the values, we get k = distance / time = 75 miles / 2.5 hours = 30 miles per hour.
b. To draw a graph comparing the distance (in miles) to the number of hours traveled, we can use a scatter plot. The horizontal axis represents the number of hours traveled, and the vertical axis represents the distance traveled (in miles). We plot the points (2.5, 75) and connect them with a line. The line will be a straight line, since the distance varies directly with time.
c. To find the constant of variation in feet per second, we need to use the given information that the car will travel 110 feet in 2.5 seconds. Similar to part a, we use the formula distance = k * time. Rearranging the formula and substituting the values, we get k = distance / time = 110 feet / 2.5 seconds = 44 feet per second.
d. To draw a graph comparing the distance (in feet) to the number of seconds traveled, we can again use a scatter plot. The horizontal axis represents the number of seconds traveled, and the vertical axis represents the distance traveled (in feet). We plot the point (2.5, 110) and connect it to the origin with a line. The line will be a straight line, since the distance varies directly with time.