Calculate the heat required to convert 175 grams of ice (at the melting point) completely to steam (at the boiling point)
To calculate the heat required to convert a substance from one state to another, we need to consider the following:
1. Heat needed to raise the temperature from the initial state to the boiling/melting point.
2. Heat needed to change the state at the boiling/melting point.
3. Heat needed to raise the temperature from the boiling/melting point to the final state.
Let's break down the calculation step by step:
1. Heat needed to raise the temperature of ice from its initial state to the melting point:
The specific heat capacity of ice is 2.09 J/g°C. We need to find the heat needed to raise the temperature of 175 grams of ice from its initial temperature (typically 0°C) to its melting point (0°C):
Heat = mass × specific heat capacity × temperature difference
Heat = 175 g × 2.09 J/g°C × (0°C - 0°C) = 0 J
Since the temperature difference is zero, no heat is required to raise the temperature of the ice to its melting point.
2. Heat needed to change the state from ice to water at the melting point:
The heat of fusion (also known as the latent heat of fusion) for water is 334 J/g. We need to find the heat required to convert 175 grams of ice to water at its melting point:
Heat = mass × heat of fusion
Heat = 175 g × 334 J/g = 58,450 J
3. Heat needed to raise the temperature of water from the melting point to the boiling point:
The specific heat capacity of water is 4.18 J/g°C. We need to find the heat required to raise the temperature of 175 grams of water from its melting point (typically 0°C) to its boiling point (typically 100°C):
Heat = mass × specific heat capacity × temperature difference
Heat = 175 g × 4.18 J/g°C × (100°C - 0°C) = 73,150 J
Therefore, the total heat required to convert 175 grams of ice (at the melting point) completely to steam (at the boiling point) is 58,450 J + 73,150 J = 131,600 J.
q1 = heat required to melt ice @ zero C to liquid H2O @ zero C.
q1 = mass ice x heat fusion of ice = ?
q2 = heat required to raise T of liquid H2O from zero C to 100 C.
q2 = mass H2O x specific heat H2O x (100-0) = ?
q3 = heat required to vaporize the liquid H2O @ 100 C to steam @ 100 C.
q3 = mass H2O x heat vaporization = ?
Total heat = q1 + q2 + q3 = ?
Post your work if you get stuck.