how many ions do each produce when in a 1.0M solution
CH3COOH
Ca(NO3)2
NaNO3
NaCl
H2SO4
To figure out this you have to be able to dissociate each one and multiply the amount of ions you get by the molarity. I believe NaCl would look like: Na+ + Cl- and because the molarity is one, you multiple it by 1. So it would be two ions, I believe.
To determine how many ions are produced when each compound is in a 1.0M solution, you need to identify the ions produced by dissociation. Here's how you can do it for each compound:
1. CH3COOH (acetic acid): Acetic acid partially dissociates into acetate ions (CH3COO-) and hydrogen ions (H+). In a 1.0M solution, it will produce one acetate ion and one hydrogen ion.
2. Ca(NO3)2 (calcium nitrate): Calcium nitrate dissociates completely into calcium ions (Ca2+) and nitrate ions (NO3-). In a 1.0M solution, it will produce two calcium ions and two nitrate ions.
3. NaNO3 (sodium nitrate): Sodium nitrate also dissociates completely into sodium ions (Na+) and nitrate ions (NO3-). In a 1.0M solution, it will produce one sodium ion and one nitrate ion.
4. NaCl (sodium chloride): Sodium chloride dissociates completely into sodium ions (Na+) and chloride ions (Cl-). In a 1.0M solution, it will produce one sodium ion and one chloride ion.
5. H2SO4 (sulfuric acid): Sulfuric acid dissociates into hydrogen ions (H+) and sulfate ions (SO4^2-). In a 1.0M solution, it will produce two hydrogen ions and one sulfate ion.
So, to summarize the number of ions produced in a 1.0M solution:
- CH3COOH: 1 acetate ion, 1 hydrogen ion
- Ca(NO3)2: 2 calcium ions, 2 nitrate ions
- NaNO3: 1 sodium ion, 1 nitrate ion
- NaCl: 1 sodium ion, 1 chloride ion
- H2SO4: 2 hydrogen ions, 1 sulfate ion